PHP Manual: Returns the number of arguments passed to the function

Description

int func_num_args()

Gets the number of arguments passed to the function.

This function may be used in conjunction with func_get_arg and func_get_args to allow user-defined functions to accept variable-length argument lists.

Parameters

This function has no parameters.

Return Values

Returns the number of arguments passed into the current user-defined function.

Errors/Exceptions

Generates a warning if called from outside of a user-defined function.

Examples

Example #1 func_num_args example

<?php
function foo()
{
    echo "Number of arguments: ", func_num_args(), PHP_EOL;
}

foo(1, 2, 3);   
?>

The above example will output:

Number of arguments: 3

Notes

Note:
As of PHP 8.0.0, the func_*() family of functions is intended to be mostly transparent with regard to named arguments, by treating the arguments as if they were all passed positionally, and missing arguments are replaced with their defaults. This function ignores the collection of unknown named variadic arguments. Unknown named arguments which are collected can only be accessed through the variadic parameter.

func_num_args